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1/5(1-x)=2x^2
We move all terms to the left:
1/5(1-x)-(2x^2)=0
Domain of the equation: 5(1-x)!=0determiningTheFunctionDomain -2x^2+1/5(1-x)=0
x∈R
We add all the numbers together, and all the variables
-2x^2+1/5(-1x+1)=0
We multiply all the terms by the denominator
-2x^2*5(-1x+1)+1=0
Wy multiply elements
-10x^3(-+1=0
We do not support expression: x^3(
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